Particle Physics Problems And Solutions Pdf

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Γμ=ℏτμ=6.582×10-222.197×10-6≈2.996×10-16 MeVcap gamma sub mu equals the fraction with numerator ℏ and denominator tau sub mu end-fraction equals the fraction with numerator 6.582 cross 10 to the negative 22 power and denominator 2.197 cross 10 to the negative 6 power end-fraction is approximately equal to 2.996 cross 10 to the negative 16 power MeV particle physics problems and solutions pdf

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